Use the equation y = mx +c
y = 2/3x +c Substitute the slope (m) in
5 = 2/3(-2) +c Substitute the point (-2,5)
5 = -4/3 +c Make C the subject
c = 19/3
y = 2/3x + 19/3 This is the equation of the line.
Next you start subbing the points A and B in separately, using the same equation.
Subbing A(x, 3)
3 = 2/3x + 19/3 Make x the subject to find it.
-10/3 = 2/3x
-5 = x
The point A is (-5,3)
Subbing B(-2, y)
y = 2/3(-2) + 19/3 y is already the subject and you just solve it
= -4/3 + 19/3
y = 5
The point B is (-2, 5)
I hope this helped you, I have also attached a photo of the written work! I'm also sorry if the answer isn't correct... >-<