Question

A fruit stand sells 6 oranges for $3 and 3 grape fruit for $2.40 .Lionel buys 10 oranges and 11 grapefruits. how much does Lionel spend on the fruit?

Answer 1

Lionel bought 10 oranges and 11 grapefruits.

6 oranges cost $3.

1 orange would cost $3/6

10 oranges would then cost $3/6 * 10 = $5.


3 grapes cost $2.40.

1 grape would cost $2.4/3

11 grapes would then cost $2.4/3 * 11 = $8.8.


Total amount spent = $5 + $8.8 = $13.8

Answer 2

6oragnes=3dollars
divide 6
1oragne=0.5dollar

3grapefruit=2.4dollar
divide3
1grapefruit=0.6dollar

10 oranges and 11 grapefuites
(10 times 0.5)+(11 times 0.6) =
5+6.6=11.6

answer is $11.6