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5/x-2 - 2/3x-5 (5)/(x-2) - (2)/(3x-5)

5/x-2 - 2/3x-5 (5)/(x-2) - (2)/(3x-5)
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5/x-2 - 2/3x-5


(5)/(x-2) - (2)/(3x-5)

User Cody S
by
8.8k points

1 Answer

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All we need to do is to have the same denominator
5/x-2 - 2/3x-5

(5)/(x-2)×
(3x-5)/(3x-5) -
(2)/(3x-5)×
(x-2)/(x-2)

(15x-25)/((x-2)(3x-5)) -
(2x-4)/((x-2)(3x-5))
Answer =
((15x-2x-25-4))/((x-2)(3x-5))
=
(13x-29)/((x-2)(3x-5))
User Abhijeet Navgire
by
8.2k points
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