73.9k views
1 vote
What is the OH- concentration of a solution whose pH is 12.40?

1 Answer

6 votes
pH + pOH = pKw = 14

12.40 + pOH = 14

pOH = 14 - 12.40

pOH = 1.6

[OH⁻] =
10 ^(-pOH)

[OH⁻] =
10 ^(-1.6)

[OH⁻] = 2.5x10⁻² M

hope this helps!
User Heejung
by
8.6k points