Question

(L012) Grades on Exam 1 for College Algebra are normally distributed with a mean

of 73 and a standard deviation of 6. What is the z-score for a grade of 62?
0 -1.83
-0.77
O
0.77
1.83

Answer 1

For a normal distribution, we can determine the z-socre by means of the following formula:

`z=(x-\mu)/(\sigma)`

Where μ is the mean and σ is the standard deviation. By replacing 62 for x, 73 for μ and 6 for σ, we get:

`z=(62-73)/(6)=-1.83`

Then, the z-score value is -1.83