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In a right triangle shaped house, the roof is 51 feet long and the base of the house is 29 feet across. Calculate the height of the ho

User Sergiomse
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2 Answers

1 vote

Final answer:

Using the Pythagorean theorem, the height of the right triangle-shaped house is found to be approximately 41.95 feet, given the base is 29 feet and the hypotenuse (roof) is 51 feet.

Step-by-step explanation:

The student is asking to calculate the height of a right triangle-shaped house, given the length of the roof (hypotenuse) and the base. This can be solved using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b): a^2 + b^2 = c^2.

Let's consider the base of the triangle as a = 29 feet, the hypotenuse as c = 51 feet, and we want to find the height, which we'll call b.

  • First, square the lengths of the base and the hypotenuse: a^2 = 29^2 and c^2 = 51^2.
  • Then, calculate the square of the base: 29^2 = 841.
  • Next, calculate the square of the hypotenuse: 51^2 = 2601.
  • Now, apply the Pythagorean theorem to find b^2: b^2 = c^2 - a^2.
  • Subtract the square of the base from the square of the hypotenuse: 2601 - 841 = 1760.
  • Finally, take the square root of 1760 to find the height b: √1760 ≈ 41.95 feet.

Therefore, the height of the house is approximately 41.95 feet.

User Giancarlo Melis
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3 votes
hypoteneuse is 51 feet and the base of the triangle is 29 feet long. use c^2-a^2=b^2
so 51^2 - 29^2 then square root it
User CarveDrone
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6.6k points
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