Question

Jika log2= 0,3010
log3= 0,4771
maka log (3√2x√3) =

Answer 1

log (3√2x√3) = log( 3 *
`3^(1/2)`* x *
`2^(1/2)` ) = log(
`3^(3/2)` * x *
`2^(1/2)` ) = log(
`3^(3/2)`) + log x + log(
`2^(1/2)` ) = ( 3 / 2 ) * 0,4771 + log x + ( 1 / 2 ) * 0,3010 = 0,7156 + 0,1505 + log x = 0, 8661 + log x.