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Solve the by elimination 5x - 3y + 4z = -6- 4x + 2y - 3z =12- x + 5y + 7z = 32 X = Y = Z =

User MappaM
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1 Answer

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The given equations are

5x - 3y + 4z = -6

- 4x + 2y - 3z =12

- x + 5y + 7z = 32

From the last equation, x = 5y + 7z - 32

We would substitute x = 5y + 7z - 32 into equations 1 and 2. For equation 1, we have

5(5y + 7z - 32) - 3y + 4z = -6

25y + 35z - 160 - 3y + 4z = - 6

By collecting like terms, we have

25y - 3y + 35z + 4z = - 6 + 160

22y + 39z = 154

For equation 2, we have

- 4(5y + 7z - 32) + 2y - 3z = 12

- 20y - 28z + 128+ 2y - 3z = 12

By collecting like terms, we have

- 20y + 2y - 28z - 3z = 12 - 128

- 18y - 31z = -116

We would solve the two equations that we got by method of elimination.

22y + 39z = 154

- 18y - 31z = -116

To eliminate y, we would multiply the first equation by 18 and the second equation by 22. We have

396y + 702z = 2772

- 396y - 682z = - 2552

By adding both equations, we have

396y - 396y + 702z - 682z = 2772 - 2552

20z = 220

z = 220/20

z = 11

By substituting z = 11 into 18y - 31z = -116, we have

18y - 31(11) = - 116

18y - 341= - 116

18y = - 116 + 341 = 225

y = 225/18

y = 12.5

Substituting y = 12.5 and z = 11 into x = 5y + 7z - 32, we have

x = 5(12.5) + 7(11) - 32 = 62.5 + 77 - 32

x =



User Artur  Dumchev
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