Question

A sample of aluminum metal absorbs 8.32 J of heat, upon which the temperature of the sample increases from 23.2 degrees C to 30.5 degrees C. Since the specific heat capacity of aluminum is 0.90 J/g-K, the mass of the sample is what in grams?

Answer 1

Given:

8.32 J of heat

from 23.2 degrees C to 30.5 degrees C

heat capacity of aluminum is 0.90 J/g-K

Required:

m in grams

Solution:

H = mCpT

(8.32 J) = m(0.90 J/g-K)(30.5 – 23.2)K

m = 1.27g