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If 5 moles of P4 reacted with 22 moles Cl2 according to the above reaction, determine:

a. How many moles PCl3 are produced ________________
b. How many moles of P4 are left in excess after the reaction (if any) ________________
c. How many moles of Cl2 are left in excess after the reaction (if any) ________________

1 Answer

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Solution:


P_4+6Cl_2\rightarrow 4PCl_3

a) By stoichoimetry If 6 moles of
Cl_2 gives 4 mole of
PCl_3 , then 22 moles of
Cl_2 will give:
(4)/(6)* 22=(44)/(3)=14.66 moles of
PCl_3

b) If 6 moles of
Cl_2 reacts with one mole of
P_4 , then 22 moles of
Cl_2 will react :
(1)/(6)* 22=(11)/(3)=3.66 moles of
P_4

Moles of
P_4 left after the reaction =
5-3.66=(4)/(3)=1.34 moles.

c) 0 Moles of
Cl_2 , since it is present in less amount it will get completely consumed in the reaction. Hence, it is limiting reagent.



User Noran
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