Question

A sequence is defined by the recursive formula f (n + 1) = f(n) – 2. If f(1) = 18, what is f(5)?

Answer 1

`f(2)=18-2=16\\ f(3)=16-2=14\\ f(4)=14-2=12\\ \boxed{f(5)=12-2=10}`

Answer 2

For this case we have the following recursive formula:

`f (n + 1) = f (n) - 2`
What we must do in this case is to evaluate different values of n until we find f (5)
We have then:
For n = 1:

`f (1 + 1) = f (1) - 2 f (2) = f (1) - 2 f (2) = 18 - 2 f (2) = 16`
For n = 2:

`f (2 + 1) = f (2) - 2 f (3) = f (2) - 2 f (3) = 16 - 2 f (3) = 14`
For n = 3:

`f (3 + 1) = f (3) - 2 f (4) = f (3) - 2 f (4) = 14 - 2 f (4) = 12`
For n = 4:

`f (4 + 1) = f (4) - 2 f (5) = f (4) - 2 f (5) = 12 - 2 f (5) = 10`
Answer:
The value of the recursive formula for f (5) is given by:

`f (5) = 10`