Given that y varies jointly as the square of x and the square of z.
When:
• x = 3
,
• z = 4
,
• y = 72
Let's write an equation describing the relationship of the given varibles.
In this case, we are to make use of the joint variation equation:
y = kx²z²
Where k is the constant of proportionality.
Let's find the value of k.
To solve for k, substitute the given values of the variables into the equation.
We have:
y = kx²z²
72 = 3²×4²×k
72 = 9 × 16 × k
72 = 144k
Divide both sides by 144:
Therefore, the constant of variation, k, is 0.5
The equation describing the relationship will be:
y = 0.5x²z²
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