Question

What is the logarithmic form of the equation e4x ≈ 2981?

Answer 1

Since it has e we can use the natural long so it would be
in2981=4x

Answer 2

`\ln(2981)=4x`

Explanation:

The given equation is
`e^(4x)\approx2981`

We can use the relation between logarithmic and exponential function.

`\text{If }y=b^x\text{ then }x=\log_b(y)`

Here,

b = e

x = 4x

y = 2981

Thus, using the above relation, we can write

`e^(4x)\approx2981\\\\\log_e(2981)=4x`

We know
`\log_e(2981)=\ln(2981)`

Hence, we have

`e^(4x)\approx2981\\\\\ln(2981)=4x`