What is the value of x in the equation 3x –1/9 y = 18, when y = 27?

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asked Jan 11, 2017 108k views

4 votes

What is the value of x in the equation 3x –1/9 y = 18, when y = 27?

Mathematics
high-school

Hjelpmig asked

by Hjelpmig

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2 Answers

1 vote

3x-1/9 y=18
if y=27
Then:
3x-(1/9)27=18
3x-27/9=18
3x-3=18
3x=18+3
3x=21
x=21/3=7

Answer: x=7

SWB answered Jan 13, 2017

by SWB

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5 votes

3x - (1/9)y = 18

Plug in y = 27

3x - (1/9)27 = 18

3x - 27/9 = 18

3x - 3 = 18

3x - 3 + 3 = 18 + 3

3x = 21

x = 21/3

x = 7

x = 7 when y = 27

Ptoinson answered Jan 17, 2017

by Ptoinson

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