Answer:
The first (smallest) integer =1
The second integer =
The third integer =
The fourth (largest) integer =
Explanations:
Let the smallest integer be represented as n
The second integer = n + 1
The third integer = n + 2
The fourth integer = n + 3
The sum of the four consecutive integers equal 462
This can be written mathematically as:
n + (n + 1) + (n + 2) + (n + 3) = 462
4n + 6 = 462
4n = 462 - 6
4n = 456
n = 456 / 4
n = 114
The second number = n + 1
The second number = 114 + 1
The second number = 115
The third number = n + 2
The third number = 114 + 2
The third number = 116
The fourth number = n + 3
The fourth number = 114 + 3
The fourth number = 117