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The science fair project s are set up on tables. There are 99 long tables used. Each long table holds 7 projects. The rest of the projects are set up on short tables. Each short table can hold 4projects. What is the fewest number of short tables that will be needed for the rest of projects

User Jasonmw
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2 Answers

6 votes

Answer:

396

Explanation:

Part 2 of question:

The science fair judges will be science teachers and volunteers. Each judge will only have time to view 5 science fair projects. there are 133 science teachers. What is the fewest number of volunteers needed to have enough judges for all projects?

133 (number of teachers)

5 (project per teacher)

133×5=665

290+665=955

User HenryTK
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7.3k points
4 votes
There are a few missing information that are pertinent to this problem.

Grade: 3 4 5
Number of science fair projects: 462 759 891

Total number of projects: 462 + 759 + 891 = 2112

99 long tables * 7 projects = 693 projects

2112 - 693 = 1419 projects

1419 projects ÷ 4 projects/short table = 354.75 tables or 355 short tables needed.

total projects: 2112
projects on long table: 693
projects on short table: 1419
User Lark
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7.3k points