Question

Two hundred grams of a substance requires 9.76 kj of heat to raise its temperature from 25degrees C to 45 degrees C

Answer 1

Given:

9.76 kj of heat

from 25degrees C to 45 degrees C

200 grams of substance

Required:

Cp in kJ/kg-K

Solution:

H = mCpT

(9.76 kJ) = (200g)(1kg/1000g)Cp(45 – 25)K

Cp = 2.44 kJ/kg-K