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Using the data of class weight , compute for the mean, median and mode.Treated as group data.

Using the data of class weight , compute for the mean, median and mode.Treated as-example-1
User Theanine
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1 Answer

19 votes
19 votes

Given:

The data of weight of the students is given:

42, 47, 67, 59, 49, 56, 59, 44, 48, 50, 63, 58, 44, 50, 72, 64, 62, 41, 46, 38, 39, 44, 78, 51, 53, 53, 56, 70, 64, 47, 51, 68, 90, 39, 44, 45, 54.

To find:

The mean, median and mode.

Solution:

The mean of the data is given by:


\operatorname{mean}=\frac{\text{ sum of all observation}}{\text{ number of observations}}

So, the mean of the given data is as follows:


\begin{gathered} \operatorname{mean}=(42+47+67+59+49+56+59+44+48+50+63+58+44+50+72+64+62+41+46+38+39+44+78+51+53+53+56+70+64+47+51+68+90+39+44+45+54)/(37) \\ =(2005)/(37) \\ =54.189 \end{gathered}

So, the mean of the data is 54.189.

To find the median, we have to find the increasing order of the given data.

The increasing order of the data is:

38, 39, 39, 41, 42, 44, 44, 44, 44, 45, 46, 47, 47, 48, 49, 50, 50, 51, 51, 53, 53, 54., 56, 56, 58, 59, 59, 62, 63, 64, 64, 67, 68, 70, 72, 78, 90.

Since the data is odd. The number of all observations is 37. So, the median of the data is:


\begin{gathered} \text{median}=(n+1)/(2)th \\ =(37+1)/(2)th \\ =(38)/(2)th \\ =19th \end{gathered}

So, the median of the data is 51.

The mode of the data is the element whose frequency is highest. Here, the frequency of 44 is the highest.

So, the mode of the data is 44.

User Csk
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