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Express the polynomial as a product of linear factors.f(x)= x3 – 5x2 – 18x+ 72A. (x-3)(x + 4)(x-6)B. (x-4)(x+3)(x + 2)C. (x-3)(x + 3)(x-8)D. (x-2)(x + 6)(x-6)

Express the polynomial as a product of linear factors.f(x)= x3 – 5x2 – 18x+ 72A. (x-example-1
User Dedek
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1 Answer

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The given polynomial is : x³ - 5x² - 18x + 72

To factorize the polynomial

In the given option the factors are (x-3), (x+4), (x - 6) (x -2), (x+2)

Apply hit and trial method

Substitute x = 3 if the polynomial satisfy then the (x - 3) is the factor

x³ - 5x² - 18x + 72

3³ -5 3² - 18 ( 3) + 72

27 - 45 - 54 + 72

0

Thus x = 3 satisfy the polynomial

hence ( x - 3) is the factor of the polynomial

Now for the other factors : Divide the polynomial x³ - 5x² - 18x + 72 by ( x - 3)

Thus, on x³ - 5x² - 18x + 72 by ( x - 3) = x² - 2x - 24

Factorize : x² - 2x - 24

x² - 2x - 24 = 0

x² - 6x + 4x - 24 = 0

x(x - 6) + 4 (x - 6) = 0

(x + 4)(x - 6) = 0

So the factors are (x + 4) (x - 6)(x - 3)

Answer : A) (x + 4) (x - 6)(x - 3)

Express the polynomial as a product of linear factors.f(x)= x3 – 5x2 – 18x+ 72A. (x-example-1
User Khadreal
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