Question

Makoto and his friends rolled 2 fair number cubes 500 times & recorded the sum of the numbers shown on the cubes each time. On 42 trials the sum was 10. which of these is most likely the probability that the sum of the numbers shown on the cubes is 10 when 2 fair number cubes are rolled?

a.) 1/6
b.) 1/12
c.) 1/25
d.) 1/50
PLEASSEEEEE HEEELLLPPP

Answer 1

1/2 anwser is B

Explanation:

rolled 2 fair number 500 times right? okay so the sum is a number of anytotal added up correct?

it was shown on the cubes each time ,so you can assume wit 42+10=52?2=x well then just divide that by 500! wich is 1/6

Answer 2

The correct answer is this one: "b.) 1/12." Makoto and his friends rolled 2 fair number cubes 500 times & recorded the sum of the numbers shown on the cubes each time.

So here it is:
1/12 42/250 = .083 1/12-.084.
There are 36 possibilities of rolls and three of them total 10.
3/36=1/12.