If x=2 and y=-3what is the value of 2x²-3xy-2y²

asked Dec 12, 2015 108k views

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$2x^2-3xy-2y^2= 2*2^2-3*2*(-3)-2*(-3)^2 \\ \\ = 2*4+18-2*9= \\ \\ =8+18-18 \\ \\ =\boxed{8}$

Jurgy answered Dec 16, 2015

by Jurgy

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