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Find the value of x when dy/dx=0: y=4x^2+2x+1 Thanks Please show full working out Note (^2 means squared).
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Find the value of x when dy/dx=0:

y=4x^2+2x+1

Thanks

Please show full working out

Note (^2 means squared).

User Rdp
by
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1 Answer

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dy/dx=8x+2
Then 8x+2=0
x=-1/4
User Svnm
by
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