Question

A spring has a spring constant of 100 N/m. When the spring is compressed by 5 mm (such that \Delta xΔx is negative), determine the restoring spring force.

Answer 1

Given that spring constant, k = 100 N/m and displacement, x = - 5mm = - 0.005 m

The formula of restoring force according to Hooke's law,

`F=-kx`

Substituting the values, we get

`\begin{gathered} F=-100(-0.005) \\ =\text{ 0.5 N} \end{gathered}`

Thus, the force is 0.5 N