Question

The sum of three consecutive even integers is 66. what is the third number

Answer 1

We can represent these three consecutive even integers as follows:

`x+x+2+x+4=66`

Then, we need to add the like terms, and:

1. Subtract 6 on both sides of the equation, and

2. Divide by 3 to both sides of the equation.

`3x+6=66\Rightarrow3x=66-6\Rightarrow3x=60\Rightarrow(3x)/(3)=(60)/(3)\Rightarrow x=20`

Then, we have that the value for x = 20, then we have that the third number is:

x + 4 ---> 20 + 4 = 24.

The third number is 24.

The other numbers are 20 (x) and 22 (x + 2). Then, we have:

20 + 22 + 24 = 66