Question 1

I need help on this I really don’t understand how to get to the answer

Question 2

Given:

$\begin{bmatrix}{1} & {2} & 3 & {6} \\ {1} & {1} & 1 & {-2} \\ {0} & {2} & 1 & {5} \\ {} & {} & {} & {}\end{bmatrix}$

Required:

$\text{We need to use the given operation }-R_1+R_2\rightarrow R_2.$

Step-by-step explanation:

$\text{We know that }R_1\text{ represents the first row and }R_2\text{ represents the second row.}$

$-R_1+R_2\rightarrow R_2\text{ means the second row of the matrix can be found by subtracting first row from second row.}$

$\begin{bmatrix}{1} & {2} & 3 & {6} \\ {1-1} & {1-2} & 1-3 & {-2-6} \\ {0} & {2} & 1 & {5} \\ {} & {} & {} & {}\end{bmatrix}$

$\begin{bmatrix}{1} & {2} & 3 & {6} \\ {0} & {-1} & -2 & {-8} \\ {0} & {2} & 1 & {5} \\ {} & {} & {} & {}\end{bmatrix}$

Final answer:

$\begin{bmatrix}{1} & {2} & 3 & {6} \\ {0} & {-1} & -2 & {-8} \\ {0} & {2} & 1 & {5} \\ {} & {} & {} & {}\end{bmatrix}$

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