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What is the equation of the line graphed below?A. y = -2xB. y = 2xC. y=-xD. y = -x56(1,2)

What is the equation of the line graphed below?A. y = -2xB. y = 2xC. y=-xD. y = -x-example-1
User Manikanta
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1 Answer

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22 votes

SOLUTION

We will take the point (1, 2) and the origin (0, 0) to get the slope m, we have


\begin{gathered} m=(2-0)/(1-0) \\ m=(2)/(1) \\ m=2 \end{gathered}

Equation of a line in slope-intercept form is


\begin{gathered} y=mx+b \\ where\text{ m = slope = 2} \\ b=y-intercept=0 \end{gathered}

so equation of the line graph becomes


\begin{gathered} y=2x+0 \\ y=2x \end{gathered}

Hence the answer is option B

User Nalu
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