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6x^3 + 9x^2 + 2x +3 factor thos expression with work?

1 Answer

4 votes
split it up an group with like ones (6x^3 with 2x since 6 and 2 are divisble by 2 and 9x^2 with 3 since both divisible by 3)
(6x^3+2x)+(9x^2+3)
undistribute using reverse distributive property (ab+ac=a(b+c))

2x(3x^2+1)+3(x^2+1)
undistribute again
(3x^2+1)(2x+3)


User Drew Angell
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