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There were 598 tickets purchased for a major league baseball game the general admission tickets cost $6.50 in the upper box tickets cost $10 the total amount of money spent was $4821.50 how many of each kind of ticket were purchased?

User Chriskilding
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1 Answer

16 votes
16 votes

Given:

a.) There were 598 tickets purchased for a major league baseball game.

b.) The general admission tickets cost $6.50.

c.) In the upper box, tickets cost $10.

d.) The total amount of money spent was $4,821.50

For us to be able to determine how many of each kind of ticket were purchased, let's first generate equations based on the given.

Let,

x = no. of general admission tickets

y = no. of upper box tickets

a.) There were 598 tickets purchased for a major league baseball game.


\text{ x + y = 598}

b.) The general admission tickets cost $6.50.

c.) In the upper box, tickets cost $10.

d.) The total amount of money spent was $4,821.50


\text{ 6.50x + 10y = 4,821.5}0

Substitute the 1st generated equation to the 2nd one and simplify.


\text{ x + y = 598}
\text{ y = 598 - x}
\text{ 6.50x + 10y = 4,821.5}0
\text{ 6.50x + 10(598 - x) = 4,821.5}0
\text{ 6.50x + 5980 - 10x = 4,821.5}0
\text{ 6.50x - 10x = 4,821.5}0\text{ - 5980}
\text{ -3.50x = }-1,158.50
\text{ }\frac{\text{-3.50x}}{-3.50}\text{ = }(-1,158.50)/(-3.50)
\text{ x = }331

Therefore, 331 tickets of the general admission were purchased.

Let's determine the number of tickets purchased for the upper box.


\text{ x + y = 598}
\text{ 331 + y = 598}
\text{y = 598 - 331}
\text{ y }=\text{ 267}

Therefore, 267 tickets of the upper box were purchased.

In Summary,

No. of general admission tickets sold = 331 tickets

No. of upper box tickets sold = 267 tickets

User Jakub Siemaszko
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