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50 J of work was performed in 20 seconds. how much power was used to do this task?
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50 J of work was performed in 20 seconds. how much power was used to do this task?

User Starre
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2 Answers

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The Correct answer to this question for Penn Foster Students is: 2.5 W

User Arjen Van Der Spek
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3 votes

Power = (amount of work done) / (time to do the work).

= (50 J) / (20 sec)

= 2.5 joule/sec = 2.5 watts .
User Luke Villanueva
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7.9k points
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