Question

I need help to find the correct answer. Can you help me with these. I would appreciate that very much

Answer 1

Given

Line is perpendicular to line

`y=(1)/(4)x-1`

and passes through point (4 , 1)

Find

Equation of line in slope intercept form

Step-by-step explanation

Slope of given line is 1/4

let slope of perpendicular line be m

then

`\begin{gathered} m*((1)/(4))=-1 \\ m=-4 \end{gathered}`

then equation of line with slope will be

`y=-4x+b`

the above line is passing through (4 , 1)

so ,

`\begin{gathered} 1=-4(4)+b \\ 1=-16+b \\ b=17 \end{gathered}`

so , the required equation of line is

`y=-4x+17`

Final Answer

Therefore , the required equation of line is y = -4x + 17