4c2+6c-3c2-2c-3 Reformatting the input :Changes made to your input should not affect the solution:
(1): "c2" was replaced by "c^2". 1 more similar replacement(s).
Step by step solution :Step 1 :
Equation at the end of step 1 : ((((4•(c2))+6c)-3c2)-2c)-3 Step 2 :Equation at the end of step 2 : (((22c2 + 6c) - 3c2) - 2c) - 3 Step 3 :Trying to factor by splitting the middle term 3.1 Factoring c2+4c-3
The first term is, c2 its coefficient is 1 .
The middle term is, +4c its coefficient is 4 .
The last term, "the constant", is -3
Step-1 : Multiply the coefficient of the first term by the constant 1 • -3 = -3
Step-2 : Find two factors of -3 whose sum equals the coefficient of the middle term, which is 4 .
-3 + 1 = -2 -1 + 3 = 2
Final result : c2 + 4c - 3