Question

Using calories, calculate how much heat 32.0 g of water absorbs when it is heated from 25.0 octo 80.0 °C. How many joules is this?

Answer 1

Q=mc(change in temp)
(32.0g)(4.18J/g°C)(55°C)= 7360J

Answer 2

Q = 1760 cal or 7356.8 J

Step-by-step explanation:

The general expression to use to calculate heat is the following:

Q = m*Cp*ΔT (1)

Where:

Q = heat in cal or joules

m = mass of the compound.

Cp = specific heat of the compound

T: change in temperature (K) or T2 - T1

Now, the reported Cp for water is 1 cal/g °C and 4.18 J / g °C, we will use both to calculate the heat in calories and joules:

Using calories we have:

Q = 32 * 1 * (80 - 25)

Q = 1760 cal

This is the heat in calories.

Using joules we have:

Q = 32 * 4.18 * (80 - 25)

Q = 7356.8 J

This is the heat expressed in Joules.