Answer:
the rate at which his body is losing heat by conduction is 93.6 J/s
Step-by-step explanation:
Given that;
surface area A = 1.8 m²
Skin temperature of the person Tp = 32°C = ( 34 + 273.15 ) = 307.15 K
Temperature of Air
= 24°C = ( 24 + 273.15 ) = 297.15 K
Temperature of wall
= 17°C = ( 17 + 273.15 ) = 290.15 K
Length ( thick dead layer = 5 mm = 0.005 m
Skin emissivity = 0.97
Rate of metabolism = 155 W
rate his body is losing heat by conduction = ?
first we determine the difference in temperature between the skin and air
so
ΔT = 307.15 K - 297.15 K = 10 K
we know that; coefficient of thermal heat conductivity of air k = 0.026 W/mK
so
rate of heat loss by conduction Q/ΔT will be;
Q/ΔT = (KA/L)ΔT
so we substitute
= ( 0.026 × 1.8/ 0.005 )10
= 9.36 × 10
= 93.6 J/s
Therefore, the rate at which his body is losing heat by conduction is 93.6 J/s