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Calculate the mass of water produced when 2.06 g of butane reacts with excess oxygen.
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Calculate the mass of water produced when 2.06 g of butane reacts with excess oxygen.

User Brandon Minton
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1 Answer

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2C4H10 + 13O2 = 8CO2 + 10H2O

1. (2.06g C4H10)/(58.12 g/mol C4H10) = 0.035mol C4H10

2. (0.035molC4H10)(10 mol H2O/2mol C4H10) = 0.177mol H2O

3. (0.177mol H2O)(18.01g/mol H2O) = 3.19g H2O
User Mualig
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