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Ben Rushin is waiting at a stop light. Turns green, ben accelerated from rest at a rate of 6.00 m/s squared for a time of 4.10 seconds.

Determine the displacement of Ben's car during this time period. Use the formula to find a solution: d=vt +1/2 at squared

1 Answer

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d= vt +.5at^2
since he started at rest, v (initial velocity) is 0
so d=.5at^2
d = .5 (6m/s^2) (4.1s)^2
then put that into a calculator.

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