Question

8. A - If a square has a length of 4x - 2y, what is its area?

Answer 1

`(16x^2-16xy+4y^2)\text{ square units}`

Step-by-step explanation:

Given any square with side length s:

`\text{Area}=s^2`

If the side length, s=4x-2y

`\text{A}=(4x-2y)^2^{}`

Next, we expand:

`\begin{gathered} A=(4x-2y)(4x-2y) \\ =16x^2-8xy-8xy+4y^2 \\ A=(16x^2-16xy+4y^2)\text{ square units} \end{gathered}`

Its area is (16x²-16xy+4y²) square units.