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11 votes
11 votes
8. A - If a square has a length of 4x - 2y, what is its area?

User Kajham
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1 Answer

14 votes
14 votes

Answer:


(16x^2-16xy+4y^2)\text{ square units}

Step-by-step explanation:

Given any square with side length s:


\text{Area}=s^2

If the side length, s=4x-2y


\text{A}=(4x-2y)^2^{}

Next, we expand:


\begin{gathered} A=(4x-2y)(4x-2y) \\ =16x^2-8xy-8xy+4y^2 \\ A=(16x^2-16xy+4y^2)\text{ square units} \end{gathered}

Its area is (16x²-16xy+4y²) square units.

User Mohsen Taleb
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