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Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form?

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Slope = (y₂- y₁) / (x₂- x₁)

Points C( 3, -5) and D (6, 0) compare to (x₁, y₁) and (x₂, y₂)

Slope = (0 - -5) / (6- 3) = (0+5) / (3) = 5/3

Slope = 5/3

Equation of line given a slope and point, y - y₁ = m(x - x₁)

m = 5/3, let point C( 3, -5) = (x₁, y₁)

y - - 5 = (5/3) (x - 3)

y + 5 = (5/3)(x - 3)

3(y + 5) = 5(x - 3)

3y + 15 = 5x - 15

3y = 5x - 15 - 15

3y = 5x - 30

Hence the equation of the line is 3y = 5x - 30
User Raymond P
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