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Write an equation in standard form for a line that passes through (2,2) and (0,-3).

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So,

The standard form is:
y = mx + b

First, we find "m," the slope. Subtract the y-coordinates from each other. Do likewise with the x-coordinates.

2 - -3 = 5
2 - 0 = 2

Slope = 5/2


y= (5)/(2) x+b

Now, we can substitute the second solution into this equation for x and y and solve for "b."


-3= (5)/(2) *0+b


-3= b

Now we have our complete equation.


y= (5)/(2) x-3
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