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5 votes
What is the slope of the line defined by the equation shown below ?
2x+3y+23=0

2 Answers

4 votes
Slope = -1.333/2.000 = -0.667 x-intercept = -18/2 = -9 y-intercept = -18/3 = -6
6 votes

Hi there!

I think the slope of the line crossing over the graph is negative.

Why?

Because y=0.666667x−7.666667 OR, read below!

We will get a negative answer, to show that our slope is negative.

We'll solve for y instead of x.


2x + 3y + 23 = 0


1) Add -23 to both sides. (We're already starting out with a negative!)


2x + 3y + 23 + −23 = 0 + −23


2x + 3y = −23


2) Add -2x to both sides.


2x + 3y + 2x = −23 + 2x



3y = 2x − 23



3) Divide both sides by 3.



3y/3 = -2x - 23/3



y = -2/3x + -23/3


So, now that we've done all 3 steps, your answer is


y = -2/3x + -23/3, which is a negative answer!


Now we see that the slope of 2x+3y+23=0 is negative.


Hope this helps! :D


Meant to add - The /'s are fraction bars

User Yan Vh
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