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40 votes
40 votes
Consider △ABC, where a = 6, c = 8, ∠C=48∘.What are the missing sides and angles

User Kaslico
by
3.1k points

1 Answer

23 votes
23 votes

Answer: A = 33.88 degrees

B = 98.12 degrees

b = 10.66

Step-by-step explanation:

From the information given,

side a = 6

side c = 8

angle C = 48

To find angle A, we would apply the sine rule which is expressed as

a/SinA = b/SinB = c/SinC

Thus,

6/SinA = 8/Sin48

By cross multiplying,

8SinA = 6SIn48

SinA = 6SIn48/8 = 0.5574

Taking the sine inverse of 0.5574,

A = Sin^-1(0.5574)

A = 33.88 degrees

Recall, the sum of the angles in a triangle is 180 degrees. Thus,

A + B + C = 180

33.88 + B + 48 = 180

B + 81.88 = 180

B = 180 - 81.88

B = 98.12 degrees

We would find b by applying the sine rule. We have

b/sin98.12 = 8/Sin48

By cross multiplying,

bsin48 = 8sin98.12

b = 8sin98.12/sin48

b = 10.66

User Hann
by
3.1k points
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