Answer:
A) -6
E) 2
F) 3
Explanation:
Given: g(x) = (x^2 + 4x - 12)(x -3)
We can factor (x^2 + 4x -12)
g(x) = (x -2)(x + 6)(x-3)
Now set g(x) equal to zero to find the zeros of the functions
(x - 2) (x + 6) (x - 3) = 0
(x - 2) = 0; (x + 6) = 0; (x - 3) = 0
x =2 ; x = -6 and x = 3
Therefore, zeros of the function are
A) -6
E) 2
F) 3
Hope this will helpful.
Thank you.