Question

What is the solution to the system of equations?

4x+y=2
x-y=3

( , )

Answer 1

4x+y=2

x-y=3

Solve 4x+y=2 for y

Add -4x to both sides

4x+y+-4x=2+-4x

y=-4x+2

Substitute -4x+2 for y in x-y=3

x-y=3

x-(-4x+2)=3

Simplify both sides of the equation

5x-2=3

Add 2 to both sides

5x-2+2=3+2

5x=5

Divide both sides by 5

5x/5=5/5

x=1

Substitute 1 for x in y= -4x+2

y=-4x+2

y=(-4)(1)+2

Simplify both sides of equation
y=-2

Answer : y=-2 and x=1

I hope that's help again !

Answer 2

ok
solution is
(x,y)

so
add the equations together to cancel y''s

4x+y=2
x-y=3 +
5x+0y=5
5x=5
divide 5
x=1
subsitute
4x+y=2
4(1)+y=2
4+y=2
subtract 4
y=-2

x=1
y=-2
(1,-2)