Question

How far apart are the slits to produce a 3rd order bright fringe at an angle of 3.52° if the light source has a wavelength of 2.58x107m?7.33x10 m1.26x105m4.20x106m2.20x107m

Answer 1

Using diffraction grating equation:

`dsin(\theta)=n\lambda`

Where:

`\begin{gathered} d=Distance \\ \theta=Angle=3.52 \\ \lambda=Wavelength=2.58*10^7 \\ n=integer_{\text{ }}number_{\text{ }}to_{\text{ }}next_{\text{ }}bright_{\text{ }}fringe=3 \end{gathered}`

Solve for d:

`\begin{gathered} d=(\lambda n)/(sin(\theta)) \\ d=((3)(2.58*10^7))/(sin(3.52)) \\ d\approx1.26*10^5m \end{gathered}`