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AngleDFG and angleJKL are complementary angles. M angleDFG =x+5, and m angleJKL=x-9. Find the measure of each angle

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Measures\ of\ complementary\ angles\ make\ sum\ equal\ to\ 90^(\circ).\\\\ \angle DFG+\angle JKL=90^(\circ)\\\\ x+5+x-9=90\\\\ 2x=90-5+9\\\\ 2x=94\ \ \ |:2\\\\x=47^(\circ)\\\\ \angle DFG=x+5=47+5=52^(\circ)\\ \angle JKL=x-9=47-9=38^(\circ)
User Esteban Herrera
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