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(3x-4)∧2=8 how do i solve this
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(3x-4)∧2=8 how do i solve this

User Sola Oderinde
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(3x-4)^2=8\iff3x-4=\pm\sqrt8\\\\3x-4=-√(4*2)\ or\ 3x-4=√(4*2)\\\\3x-4=-2\sqrt2\ or\ 3x-4=2\sqrt2\ \ \ \ \ \ \ |add\ 4\ to\ both\ sides\\\\3x=4-2\sqrt2\ or\ 3x=4+2\sqrt2\ \ \ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x=(4-2\sqrt2)/(3)\ or\ x=(4+2\sqrt2)/(3)}
User Rcorty
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