Question

If x,y and z are positive integers and 3x=4y=7z, then the least possible value of x+y+z=?

Answer 1

Multiply 3x4x7 to get the lowest number they will all go into. Then divide by the number you're trying to figure out (exp. 84/3=28) X=28 y=21 z=12 :)

Answer 2

integers
positive
okso therefor
3x=some number
4y=some number
7y=some number

therefor, this 'some number' must have factors of 3,4,7

find greatest common multiplule
3=3
4=2 times 2
7=7
3 times 2 times 2 time s7=84



3x=4y=7z=84
solve
3x=84
divide 3
x=28

4y=84
divide 4
y=21

7y=84
divide 7
y=12


so
x+y+z=28+21+12=61