Answer:
Step-by-step explanation:
NaOH + HCl = NaCl + H₂O
1 mole 1 mole 1 mole
6.93 g of HCl = 6.93 / 36.5 mole = .19 mole
2.4 g of NaOH = 2.4 /40 mole of NaOH = .06 mole
.06 mole of NaOH is less than .19 mole of HCl so
limiting reagent is NaOH
.06 mole of NaOH will react with .06 mole of HCl to give .06 mole of water .
water formed by given mass of reactants
= .06 moles of water
= .06 x 18 gram of water
= 1.08 g of water .
= 1.1 g of water .