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3ax-n/5=-4 solve for x

User Catalpa
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1 Answer

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3ax-(n)/(5)=-4\ \ \ |Add\ (n)/(5)\ to\ both\ sides\\\\ 3ax=-4+(n)/(5)\\\\ 3ax=-(20)/(5)+(n)/(5)\\\\ 3ax=(-20+n)/(5)\ \ \ |Divide\ by\ 3a\\\\ x=(-20+n)/(5)*(1)/(3a)\\\\ x=(-20+n)/(15a)\\\\Asnwer\ is\ x=(-20+n)/(15a).
User Tschoartschi
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