Question

What would the molarity of a NaOH solution that was made by taking 45.5 mL of 0.875 M NaOH and then diluting with water to a total volume of 500 mL?

Answer 1

0.0796M

Explanation;

Using the dilution formula:

`C_1V_1=C_2V_2`

where:

C1 and C2 are the initial and final concentration

V1 and V2 are the initial and final volume

Given the following parameters

C1 = 0.875M

V1 = 45.5mL

V2 = 500mL

Required

Final concentration C2

Substituting the given parameters into the formula

`\begin{gathered} C_2=(C_1V_1)/(V_2) \\ C_2=(0.875*45.5mL)/(500mL) \\ C_2=(39.8125)/(500) \\ C_2=0.0796M \end{gathered}`

Hence the final concentration is 0.0796M